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-70+25x+5x^2=0
a = 5; b = 25; c = -70;
Δ = b2-4ac
Δ = 252-4·5·(-70)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-45}{2*5}=\frac{-70}{10} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+45}{2*5}=\frac{20}{10} =2 $
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